DecreaseThis time I have a skillet that is 240 3ph 15kw,if I provide a supply voltage of 208 does the current increase or decrease?
No, current will go up on 208v vs 240v.Decrease
If you're citing Ohm's Law, you have it backwards. Ohm's Law is for simple resistive loads, like an electric skillet.The current will go up on 208v vs 240v.
Any time you apply a lower voltage to the same load, the current will always go up (Ohm’s Law).
LOL!62 amps at 240v, 72 amps at 208v.
Hell of a skillet62 amps at 240v, 72 amps at 208v.
Ohm’s Law also covers current.If you're citing Ohm's Law, you have it backwards. Ohm's Law is for simple resistive loads, like an electric skillet.
V=IR
Solving for I, the current
I = V/R
R is the resistance of the electric skillet. That does not change, so any value can be used. Let's say the resistance is 8 ohms.
V is voltage, 240 vs. 208
I = 240 V/8 Ohms = 30 Amps
I = 208 V/8 Ohms = 26 Amps
For an inductive load you would be correct, but then it has nothing to do with Ohm's Law.
Say what?The current will go up on 208v vs 240v.
Any time you apply a lower voltage to the same load, the current will always go up (Ohm’s Law).
If you reduce voltage, amperage will also go down, (and likewise power goes down). An electric skillet is purely resistive load. If it is rated 15kw with a 240v supply, then that's 62.5 amps of current. Ohms law written for resistance is R=V/I. This means the skillet has a resistance of 3.84 ohms. If the only change is dropping the voltage down to 208, then ohms law in terms of current is I=V/R which means the skillet will then be passing 54.17 amps, which then means it's only outputting 11.27kw of power (P=I*V).Ohm’s Law also covers current.
Also, your amps are wrong. At 15kw the skillet will draw 62.5 amps at 240v and 72 amps on 208v. Watts divided by volts will get you your amp draw. Ohms law covers this.
Wrong! You might be about right IF he had single phase device, but not even in same ball park for his three phase device. Posters really should not be trying to give advice on things they know nothing about.If you reduce voltage, amperage will also go down, (and likewise power goes down). An electric skillet is purely resistive load. If it is rated 15kw with a 240v supply, then that's 62.5 amps of current. Ohms law written for resistance is R=V/I. This means the skillet has a resistance of 3.84 ohms. If the only change is dropping the voltage down to 208, then ohms law in terms of current is I=V/R which means the skillet will then be passing 54.17 amps, which then means it's only outputting 11.27kw of power (P=I*V).
Nope, I am correct. My degree is Electronics Engineering Technology. If the only thing changing is the voltage decreasing, then current MUST also decrease. 240v 3-phase is very rare, but might be possible that's what he has. Some erroneously call 240v single phase "three phase" when they're using two legs of 120 to get that 240. If it is true that he actually has 240 3-phase, then connecting it to 208 3-phase is only reducing the voltage to a purely resistive load.Wrong! You might be about right IF he had single phase device, but not even in same ball park for his three phase device. Posters really should not be trying to give advice on things they know nothing about.
S
I just arbitrarily picked a resistance value because it is the same in either case just to demonstrate the relationship.Ohm’s Law also covers current.
Also, your amps are wrong. At 15kw the skillet will draw 62.5 amps at 240v and 72 amps on 208v. Watts divided by volts will get you your amp draw. Ohms law covers this.
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