rustred

Well-known Member
just come up with a crazy cynario , if you somehow pulled your truck tire under water with 55 lbs of air in it, would the pressure push it
off the rim. at the titanic depth they say the pressure is 6000 psi . under about two and a half miles of water. and if it would at what
depth would this happen. i do not know how to even start figuring this out.
 
The air pressure INSIDE the tire is pushing OUT (EXplosion) while under water that pressure is pushing IN (IMplosion) ... I you have 55 PSI pushing OUT with 6000 PSI pushing IN hmmmmmmmmmmmmmmmmmmmm

John T Electrical NOT Mechanical engineer so nooooooooooo warranty see what others or enginners or Google users have to say
 
If I remember from fire department hydraulics 2.31' of water = 1 psi at 60 degrees F. So at a depth of 127' the pressure inside the tire is about the same as the pressure outside. No idea how much force is required to unseat the bead.
 
ok, i was thinking if the tire had no air in it, it would just squish the sides together and dont know if it would unseat the beads. guess the rim width would come into play also , dont know.
 

My guess is as the tire goes down the water pressure will rupture the tread or sidewall before it ever squeezes the beads towards each other and off the rim.
 
(reply to post at 13:28:49 07/01/23)
It might only twist the bead enough to allow water in and the air out fast enough that the bead would not get pushed off the rim.
And the tire and bead would go back to it's original shape.
 
5TUAHLFBZZGFFCOFMZYRJCHWIY.jpg


IH tug at 17,500 feet deep.

wreck-dives-truk-lagoon.jpg


Another tractor at 120'.

https://www.navytimes.com/news/your...doolittle-raid-located-miles-below-the-waves/

https://www.sportdiver.com/worlds-10-best-dive-wreck-locations#page-3
 
I watched tires being put on wheels and inflated at a dodge assembly plant in St. Louis. The rim was held in a linear moving fixture, the tire was pinched from the
outside to about i/2 thickness (bead toward Bead) the tire was held from moving and the rim was forced up and into the tire, dragging it on the rim. Down the line 5ft a
plate bigger than the tire was moved down covering the tire and compressing the (now loose) sidewall about an inch. Massive air was pushed into this sandwich at maybe
100PSI. tht top plate was released with a bang and the tire was mounted and inflated. The pressure was adjusted to about 50psi for shipment, to keep them from
flatspotting. My experience was a bit different in that it was 1971, and steel wheels.
I think that without sudden uniform pressure increase, the others have described a rim leak that allowed water in without demounting. Jim
modern version
 
I just ate a big plate of walleye and perch that i caught yesterday in Saginaw Bay. I am not sure if the feeling i am having right now is one of implosion or explosion.
 
On a tire with a tube like those tractors in the picture the water pressure is just going to push the valve stem in the rim and the tire will fill with water pressure equal to the outside of the tire so it will stay on the rim.

On a tubeless tire the pressure will flatten the tire. It might rip the tire or it might push it off the rim. But as the water rushed in the pressure will equalize inside and out and the tire will take its normal shape.
 
Tire air pressure is obviously an outward pressure. But under water pressure, is an inward pressure against the air pressure within the tire. At a certain depth, the pressure would be equalized (as in 32 lbs of air pressure internally, and 32 lbs of water pressure externally against the internal air pressure. But going on down deeper than that, the water pressure gets greater, and the space of the air begins to get restricted to a smaller space. Compressing the air into a smaller space would increase air pressure until one of two things happened. Either the tire would blow from being imploded, or it would lose its air by some other means such as pushing the bead inward off the rim. John in LA, makes a good point about tubes if it's not a tubeless tire. Valve stem hole would change things, and I can see what he's saying about that. In that case, it's probably logical that the air space would keep getting restricted down further until the rising air pressure inside the restricted space popped it's way out of the tube. This would likely happen inside the tire carcuss itself, and the escaping air from the tube would likely just make its way out the valve stem hole.

At 6,000 psi underwater pressure, the water is basically going to get into where any air is, and take up that space instead of the air. Once that happens, the show is over. The only way to prevent this from happening, is to keep the water out of that air space. No small feat at 2 and a half miles down.
 
I would be willing to bet those tubes on the tractor tire still has the original air in them.

What makes a tube pop is the rubber can not hold the pressure inside the tube to the relation of the pressure on the outside of the tube.
Lets say you fill a tube to 50 lbs inside the tube and the outside pressure is 14 lbs of our atmosphere. The tube stretches and then blows because it can not hold the outward force.
But if we increase the outside force on the tube to 50 lbs it would be like the tube had 14 psi in it IE equal on inside and outside.

So the tubes on these tractors have 6000 psi of air pressure in them but the tube does not feel it because the water pressure from all sides pushing in is 6000 psi also.
As long as we keep the inside pressure the same as the outside pressure the tube will hold the air just in a lot smaller space as you compress the air inside. That is until the tube rots away.

What makes something implode or explode for that matter is the structure can not hold the pressure difference from inside to outside. As long as the pressure on the inside stays the same as the outside no implosion or explosion can happen.
 
Not sure if implosion would work.
To answer your question, every 28 inches of depth, water exerts 1 more pSI.
 
(quoted from post at 09:30:23 07/01/23)
My guess is as the tire goes down the water pressure will rupture the tread or sidewall before it ever squeezes the beads towards each other and off the rim.

The weakest link will fail first.

I'm thinking the valve stem will fail first.
 
I was thinking that too, if a push in type.
Since it is a truck tire, what if it had a wrenched in type valve?
And if the cap is not on or even if it is, higher than air psi water would push it's way inside the tire
or tube.
Maybe.
 
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